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Post by scamp on Dec 9, 2013 17:56:51 GMT -6
Nasty one Spock! Here's an easy one: there are three words in the English language that end with "gry." One is hungry and the other is angry. What is the third word? Everyone uses this word every day, everyone knows what it means, and knows what it stands for. If you have listened very closely I have already told you the third word. The way this is worded, I cannot think of any other words that end in "gry" that everyone uses every day that would not be not archaic. If you were to enunciate the riddle, then there is much more scope for interpretation. BOL!! Just for that I'm going tell everyone that when they naed those 3 new moons of Pluto (or wherever), the rejected Spock because it wasn't logical! guess you proved them wrong .
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Post by Spock on Dec 9, 2013 22:56:16 GMT -6
What, are you trying to imply that I solved the riddle!? Fascinating.
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Post by scamp on Dec 2, 2014 22:26:02 GMT -6
Well sort of. Think of three words ending in -gry. Angry and hungry are two of them. There are only three words in the English language. What is the third word? The word is something that everyone uses every day. If you have listened carefully, I have already told you what it is.
According to proponents of this version, the answer to the riddle is the word "language." This makes sense when you reduce the riddle to its two central sentences: "There are only three words in the English language. What is the third word?" (or, in other words, "What is the third word in the three-word phrase the English language?").The mention of words ending in -gry is a smoke screen. The riddle is "What is the third word in the three-word phrase the English language?"
A second answer Those who prefer this version of the riddle say that the answer is the word "what." Notice that the sentence "What is the third word" is not followed by a question mark, so it's not a question; it's a statement of the answer, "What is the third word." Here again, the words ending in -gry are supposedly just a smoke screen.
A NEW RIDDLE (tis easy)
If it’s certain information you seek, come and see me. if it’s pairs of letters you seek, I have consecutively three.
Who am I?
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Post by Spock on Dec 3, 2014 12:55:37 GMT -6
Of course, if you approach the previous riddle phonetically, I think you will agree there is another possibility.
As for your new riddle, I would imagine it would have to be someone involved with books; a librarian, a bookseller, or someone who just keeps books ...
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Post by stepper on Dec 3, 2014 18:34:59 GMT -6
BOLL! That was wonderfully subtle Spock. I think your answer is as good as the question. Nice riddle Scamp!
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Post by katina2nd on Dec 4, 2014 22:09:43 GMT -6
Hey, great to see you back Scamp.
I'd have a crack at your riddle, but those dang things give me a headache.
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Post by Phalon on Dec 6, 2014 9:52:14 GMT -6
Me too, Katina!
I thought Spock had it right with one of his three answers, and then, Wham!, it hit me out of the blue. Although each of his answers have three pairs of letters, none of them have three consecutive pairs of letters. And so, borrowing from his idea of the answer having to do with books (because I never would have come up with that on my own), I think I might have it...
Stellar book seller - as in a book seller who is particularly good at selling books.
Good book seller - as in a book seller who only sells best selling books.
Oh!
Good Book seller - as in a traveling salesman who sells Bibles.
Oh! Oh! Oh!
Door-to-door sleezy Good Book salesman - as in Addie's swindling father in the movie Paper Moon
I should get some kind of bonus points for that one.
But while all those good books and Good Books and good sellers of books may be informational, they aren't necessarily where you'd turn to first for information; Scamp's riddle specifically said if it's "information" you seek...
So let your fingers do the walking through the Yellow Pages Business Phone Book - is there still such a thing? Was there ever.
We are certain now why I don't attempt riddles, aren't we.
Wait!
The South Haven crabby Library Biddies
aka
The crab-ass biddies who used to give me the Evil-eye Bore-into-my-soul Stare-of-Death whenever I returned an overdue book, who have now all retired and been replaced by nice librarians.
And that is my final wrong answer.
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Post by katina2nd on Dec 6, 2014 17:24:28 GMT -6
No idea if your answer is right or not Gams, tis danged funny though, think my headache this time is caused by laughing.
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Post by stepper on Dec 7, 2014 18:00:24 GMT -6
Wrong or not, it’s an excellent answer.
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Post by scamp on Dec 7, 2014 23:51:44 GMT -6
LOL, Spock! Your answers are delightful So I've got one dedicated to you and Stepper The numbers involved are greater or equal to 2. Stepper gets the sum of the 2 numbers, you, Spock gets the product of the same 2 numbers. Question: Sum Sam and Product Pete are in class when their teacher gives Sam the Sum of two numbers and Pete the product of the same two numbers (these numbers are greater than or equal to 2). They must figure out the two numbers. What are the numbers? And thank all of you for the hugs! Scamp
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Post by stepper on Dec 15, 2014 18:44:44 GMT -6
Since I can't use zero, I don't see the solution without additional information.
If S=RND1 + RND2 and P=RND1 * RND2 and no other factors are given...
well, my slide rule said "What?"
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Post by scamp on Dec 24, 2014 5:50:33 GMT -6
Stepper, the sum of your two numbers is less than 10.
HTH, scamp
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Post by Spock on Dec 24, 2014 12:22:27 GMT -6
Since I can't use zero, I don't see the solution without additional information. If S=RND1 + RND2 and P=RND1 * RND2 and no other factors are given... well, my slide rule said "What?" Hmm, since you don't know the answer, how am I supposed to know it!? I think she should have actually given each of us the actual sum or product.
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Post by Phalon on Dec 24, 2014 16:57:52 GMT -6
Why can't it just be 2? (She never said they had to be different numbers.)
Reason I don't do math, and don't do riddles.
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Post by scamp on Dec 29, 2014 18:30:49 GMT -6
Okay, okay, I'll give it away... The sum is 7.
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Post by Spock on Dec 30, 2014 9:06:52 GMT -6
Hmm, knowing the sum and that there are only two numbers, the answer is oblivious ...
It would have to be 12 and -5.
Oh wait, negative numbers probably aren't allowed, so my first guess above must be the product. Now if I can just turn up my math co-processor so I can figure out what the individual numbers would be ...
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Post by scamp on Feb 3, 2015 5:40:40 GMT -6
Oh Spock, you do have it but you don't believe it. You've deduced the product which is 12 and you know the sum is 7, right? The only two numbers that could equal a sum of 7 and a product of 12 are........
3 and 4
Ok, someone else post a bloody riddle, my mind is sore.
scamp
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Post by stepper on Mar 2, 2015 21:20:19 GMT -6
I came across a puzzle at work and I'm embarrassed to admit it took me way too long. Here's the puzzle - with my apologies to Phalon – quoted exactly as it was presented to me.
Use this set of numbers to achieve the target number. You can use these four numbers and four arithmetic functions: addition, subtraction, multiplication, and division. Each number and result can only be used once.
7 9 20 50 Result: 203
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Paladin
Whooshite Apprentice
Posts: 104
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Post by Paladin on Sept 13, 2015 12:11:14 GMT -6
(9+20)*7
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Post by stepper on Sept 23, 2015 21:24:29 GMT -6
Without looking at a calendar....
2016 is a leap year, so with the extra day, how many Saturdays will there be?
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Post by Mini Mia on Sept 23, 2015 21:31:57 GMT -6
One per week.
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Post by Phalon on Sept 24, 2015 6:16:34 GMT -6
Ooo, good answer, Joxie. I wonder though if it's correct? What if the year, for example, ends on a Wednesday? Then technically, there wouldn't be a Saturday in that last week of 2016.
The answer probably involves some ridiculous mathematical equation that involves calculating the distance between the moon and Pluto when Jupiter aligns with Mars, dividing that distance by the speed of a train traveling west from Detroit at 7pm on Leap Day evening and arriving in Anchorage, Alaska at 7:43am two days later, with 43 minute stops in Chicago, Bismark, North Dakota, and Portland, Oregon, and multiplying that by pi.
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Post by Spock on Sept 24, 2015 7:58:58 GMT -6
I think she's on to us step ...
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Post by Spock on Sept 24, 2015 8:06:20 GMT -6
Without looking at a calendar.... 2016 is a leap year, so with the extra day, how many Saturdays will there be? 366/7= (approximately) 52.2857142857143 (to the limits of my feeble brain) or 52 Saturdays with a possibility of an additional one in the extra two days left over. I'm going to go out on a limb here and "assume" that, since you've posed the question, that there is an extra Saturday amongst those extra two days, making 53 Saturdays in 2016.
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Post by stepper on Sept 24, 2015 16:56:10 GMT -6
Then I'd have to ask how many weeks there are because rounding might apply - except for Phalon who doesn't go around, come around, or just plain mathmatically round.
Certainly the best answer and the closest! If only you had included the time warp encountered by the forced passage in Canada.
She could have been but she only gave the theoretical formula without actually executing the math. And as my teachers always said, show your work not just the answer.
This actually started because I do a weekly e-mail at work and recently I've been including triva questions. While researching autumn trivia I ran into the above question, but it pertained to 2012. The answer was 52 - the one day didn't matter. Updating it for the next leap year in 2016 required a quick check for accuracy - I don't want to be caught being wrong. Under normal circumstances the year begins and ends on the same day. The first day of 2016 occurs on a Friday meaning normally the year would also end on Friday but being a leap year, the extra day pushes it out to the next day. Saturday. The second day of next year is a Saturday and so is the last one.
There are 53 Saturdays in 2016.
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Post by Scrappy Amazon on Jan 30, 2016 16:54:03 GMT -6
Completely stuck.....maybe some brainiacs can help me with this?
Find the missing number in the following sequences:
2, 4, 8, 1, 3, 6, 18, 26, ?, 12, 24, 49, 89, 134, 378, 656, 117, 224, 548, 1456, 2912, 4934, 8868, 1771, 3543, ... -101250000, -1728000, -4900, 360, 675, 200, ?, ... 321, 444, 675, 680, 370, 268, 949, 206, 851, ?, ...
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Post by stepper on Jan 30, 2016 23:45:04 GMT -6
52
I have a sort of explanation for the first one. It's a simple multiplication pattern with an extra step.
You want a pattern of 2, 4, 8, 1, 3, 6, 18, 26, ?, 12, 24, 49, 89, 134, 378, 656, 117
It's 52. But the real question is why?
Start with 2 and multiply by 2, then multiply the result by 2. This gives you:
2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768, 65536, 131072
See it yet? The extra step is to record only the odd digits of the product, meaning if the result is six digits, 123456, you'd keep only digits 1, 3, and 5, so you'd represent 123456 as 135.
The above reply becomes:
2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768, 65536, 131072
Hopes this helps you out.
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Post by Scrappy Amazon on Jan 31, 2016 17:30:32 GMT -6
OMG...(forehead slap)...I totally see the first part except the second part doesn't follow. If you are only keeping odd numbers then this: 2, 4, 8, 16, 32, 64, 12 8, 25 6, 51 2, 10 24, 20 48, 40 96, 81 92, 16 38 4, 32 76 8, 65 53 6, 13 10 72 Falls apart after the fourth set. Unless you mean (which obviously works out) every other number as opposed to odd numbers.
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Post by stepper on Jan 31, 2016 20:27:05 GMT -6
My apologies Scrappy - Phalon has had to put up with my random thoughts long enough she's usually able to follow where my mind has wandered, but I have tried correcting this particular failing in the next response. What I was talking about was not odd numbers specifically, but odd positions in the progression. Keep position 1, position 3, position 5, but ignore the others. And yes, if you consider it starting with position one and keeping every other position, that would lead you to the correct digits.
So, let me get exotic again and hopefully explain it better than last time.
Solution for sequence 3: Okay, let me say the person who dumped these on you is not a friend (meaning these are on the difficult side). And, most likely knows something about either cryptography or cryptology or both. I have an answer for the third sequence, but again, I don't know that I can explain it well enough.
It's a mathematically progressive puzzle. You take each group of three digits in terms of each group having three positions which are related to the next group, and it's the individual positions within the groups that solve the problem.
You have three numbers in each group, and you have three progressions through the positions to derive three separate terminal digits. Those three terminal digits are the solution. The progressions are based on group 1 (and single digits - in the second group "10" becomes "0", etc.) so think of it as: start at group one/position one and go +1, the second should be handled as start at group one/position 2 and go +2, with the third starting at group one/position 3 and is +3.
The source digits are: 321, 444, 675, 680, 370, 268, 949, 206, 851, ? Round one: 3.. .4. ..5 6.. .7. ..8 9.. .0. ..1 -> the next number is 2. Round two: .2. ..4 6.. .8. ..0 2.. .4. ..6 8.. -> The next number is 0. Round three: ..1 4.. .7. ..0 3.. .6. ..9 2.. .5. -> the next number is 8.
I have this in note pad set to fixed a length font. Whoosh will change it to a proportional font so the alignment will be goofy. If you put it in a word processor using a proportional font and align the numbers to start in the same position, my inadequate explanation might make a bit more sense. In any case, the third solution is 208.
I still haven't come up with a solution for the second number sequence.
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Post by Scrappy Amazon on Jan 31, 2016 21:23:15 GMT -6
Ok....allow me explain how I got this particular puzzle after I explain what it's for. When solved (which I appreciate you handily solving for me after I stared at them for pretty much literally three hours) if you put the three answers together they make an IP address which leads to the next puzzle. This is the fourth in a string of five. I solved the first three and since math is not my thing I got completely stuck! Here's a link to the rest of the puzzles if you care to jump in. www.gchq.gov.uk/press_and_media/news_and_features/Pages/Directors-Christmas-puzzle-2015.aspx
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